2n^2+3n=n(2n+1)+16

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Solution for 2n^2+3n=n(2n+1)+16 equation: 


Simplifying
2n2 + 3n = n(2n + 1) + 16

Reorder the terms:
3n + 2n2 = n(2n + 1) + 16

Reorder the terms:
3n + 2n2 = n(1 + 2n) + 16
3n + 2n2 = (1 * n + 2n * n) + 16
3n + 2n2 = (1n + 2n2) + 16

Reorder the terms:
3n + 2n2 = 16 + 1n + 2n2

Add '-2n2' to each side of the equation.
3n + 2n2 + -2n2 = 16 + 1n + 2n2 + -2n2

Combine like terms: 2n2 + -2n2 = 0
3n + 0 = 16 + 1n + 2n2 + -2n2
3n = 16 + 1n + 2n2 + -2n2

Combine like terms: 2n2 + -2n2 = 0
3n = 16 + 1n + 0
3n = 16 + 1n

Solving
3n = 16 + 1n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1n' to each side of the equation.
3n + -1n = 16 + 1n + -1n

Combine like terms: 3n + -1n = 2n
2n = 16 + 1n + -1n

Combine like terms: 1n + -1n = 0
2n = 16 + 0
2n = 16

Divide each side by '2'.
n = 8

Simplifying
n = 8

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